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Below is a Right Hand end section of the Royal Cubit Rod.
This section of the rod has been enlarged and reversed to a negative form only.
The Rod is read from Right to Left.
Numbering is from Right to Left example;
(First Graphic = CKC-Column 1-Row 1)
CKC-C1-R1
Firstly the graphic above has not been MANIPULATED in any way except for the coloring and superimposed cross lines.
Being enlarged to this extent and to be so exact makes one question who produced the rod.
It is possible to extract the Basic Design of the GP from this enhancement.
To understand where I am coming from please note the following features.
- The internal area is not a square.
- Height = 9 Squares; Width = 10 Squares. (internal)
- 3 White Squares off-set internally.
- 1 Purple Diagonal
My thanks to The Google Team for making these pages available.
EOH CIRCUMFERENCE IMAGE DECODED
EOH SUP. HYPOTENUSE IMAGE DECODED
The above image is great example of how my decoding system works
as it is not directly related to the Pyramids.
Displaying a storyline as well as mathematical properties.
The storyline tells of Tilling,Growing,Reaping,Winnowing,Storing
of two crops (hoe and sickle in two pieces each)
and Distribution of the harvest over one year.
The maths gives the number of days in one year.
Lower Section Members.
Leg. Value(V) = 13+2(leg consists of 2 sections) = 15.
Tail. V = 11+3 (tail consists of 3 sections) = 14.
Lower Eye Socket. V = 520
Lower Eye Socket. V = (520 + 5 (Lower Eye Socket consists of 3sections + 2 sections at Junction) = 525.
Total Lower Section Value = 525/14/15 = 2.5
Top Section Members.
Eye White. V = (1and1/2) (consists of 2 pieces positioned over EW)
Eyeball. V = 90 (full eye exposed).
Eye Socket. V = 135 (90*1.5) +
Extra Pieces. V = 11.1 (9.1 includes eyebrow) + (2 @ Socket Junction).
Total top section value = (90*1.5) = 135 + (11.1) = 146.1.
The lower value is now multiplied by the top value.
Calculation; 2.5 * 146.1 = 365.25
The exact number of days in one year.
EOH CIRCUMFERENCE IMAGE DECODED
EOH SUP. HYPOTENUSE IMAGE DECODED
This main graphic supplies the values for each of the 36 divisions surrounding the EOH
REVISED 7/4/2006
Please relate to where the members of the eye point to the coding numbers on the graphic.
Tail = 11 Leg = 13 Spur = * 10 Eye Socket Junctions = 9+9 (Left andRight)
EyeBrows = 7 + 7 (Left and Right)
Lower Eye Socket = 52
There is a storyline displayed in most images, this one indicates Half Circumference to the Author but could also be interpreted as Diameter or Diagonal as the eye is spread across the whole circle.However the eye is the key to this image. = (Half)
The Unit of Measure is the Royal Cubit.
Firstly values must be applied the Eye Junctions and the Eye Brow.
Eye Junctions Value = ( 9 + 9 * 10 (Spur) = 180
Eye Brows Value = ( 7 + 7 * 10 (Spur) = 140
Adding the Values = 320
Calculation;
(320 / 52 * 13 * 11) = 880
Reversed; (880 / 11 / 13 * 52) = 320
880 Cubits equals Half the Perimeter of the Basic Pyramid Design based on the Dimensions taken from the South East Quadrant displayed in the graphic;
CKC-C1-R
Controversial or not I hope to demonstrate the only possible way the Ancient Egyptians (AEs) constructed the Great Pyramid (GP).
A good read of the book;Atlas of Ancient Egypt by Baines & Malek (B&M) is warranted here to familiarise ones self with what known materials that were available to the Ancient Egyptians at the same time taking notice of all the details in the photographs displayed. (At least 2 reads recommended).
Understanding the properties of Calcined Gypsum (CG) and Calcined Limestone (CL) is a must.
Search; (CG) http://www.artmolds.com/ali/history_plaster.html
Cement; (CL) With the dry process raw materials are dried before or during grinding. The principal raw materials are Limestone, silica sand, clay, shale, oxides of chalk. Silica , aluminum and iron are added in the forms of sand, clay, shale, sea shells (medium size particles of sedimentary layers, like clay, iron oxide, Gypsum.
Coal was also available.(B&M)
A hands on approach is a good idea to help ones understanding of what can be achieved with little cost while gaining the fundamental principals of the ancient's know-how
Example; The models in the picture below were all created with similar materials available to the AEs.
With the knowledge gained from these exercises I decided to apply what I had learnt to a full size project such as this Adobe Oven below.
Pictures somewhat compressed sideways;
From the pictures you can see how a Plug is formed simply buy using koolite boxes, house bricks and a stabilized clay-sand mix.
Stabilised Sand can be formed by combining any sought of fine mineral with (CG) and or (CL) with water. The ratio of sand to (CG) or (CL) is between 10 and 15 to one.
After the final layup the Plug is removed through the doorway.
The design of this oven was taken from a French- Canadian site. Notice the angle produced by the CAD after following the (interior dome height) to (top of door height) dimensions given in the instructions. ( 26 deg. bottom right of pic )( broken line )
Firing the oven (trenches) with minimum fuel and to achieve maximum heat is the secret to the ancient way of processing quarried materials.
Firing Oven:
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The oven is fully stoked with logs ( 6"- 12" )leaving enough room just inside the doorway to start a small starter fire.
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Once the starter fire is reduced to coals or the main logs have just caught the oven is closed up to what we know today as; ( Slow combustion state )
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24hrs in this mode will SUPER HEAT (SH) the fuel load as well as preheating the oven. ( 85% of SH-ed fuel load will still remain.)
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By opening the door the fuel load will instantly burst into action. As the oven has no exhaust it's SHing capabilities are somewhat reduced.
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To obtain the SH stage I require, compressed air is introduced to the oven.
A close look at this quarry below shows that the trenches were excavated by hand to form blocks or "cubes".
Assuming the ancients had nothing harder than copper or flint tipped picks the material must have been reasonably soft, that being the case the method of cutting out blocks, levering onto sledges, hauling them up the pyramid, that alone pulling them around corners and then levering them backwards and forwards enabling them fit them to the adjoining blocks is just not on. The block would have fallen apart even before they left the quarry! There had to be another way?
We know the quarry was made up of sedimentary materials, so why do they appear to be "ROCK?"
We need to look no further then the creamy colored material under the rock-like crust where the cubes were removed.
This is what we need to look at not the dark top cover crust.
The next graphic will throw a little light on the subject.
Grass, topsoil and human form for orientation only;
Using nothing more than the oven firing principle to fire the trenches a situation would have been created whereby the materials were calcined. Naturally the trenches were filled to the top with fuel such as animal manure, wood, coke and or coal.
The first 6"to 1' of the cubes and ceiling would virtually have become red hot.Once the material cooled down the removal would be quite easy as it's structure is weakened considerably.
The vertical washouts or erosion cavities on the quarry face indicate where the exhausts were located, being subjected to the most and prolonged SH.
Basically the internal material of the "cubes" with water added would make up the main fill mixture for the core of the pyramid.
The outer core material facing the weather would need an extra
additive such as a clinked limestone, iron oxide, clay, sand and aluminates pulverized into as we know as cement.
http://www.answers.com/topic/cement
The remaining surfaces such as the new quarry face and cube bases would have set rock hard being exposed to moisture from the (atmosphere, surrounding material or rain). The dark color is attributed to oxidation.
Quarry #2.
The method used in this quarry shown below was basically used for extraction, pulverizing and transportation to a distant site. Please note the out crops on the left hand side of the photo
A close up of the out crops in the same quarry.
Oviously the face of the quarry was accessed by the ramp which is still visible.
The out crop holds a lot more secrets.
On close inspection note the darker color of the outcrops compared to the quarry face, this indicates a much harder substance.
Note the seize and number of the pounding like marks on it's surfaces, most visible on the left hand side.
A rough base was formed to level the site (visible) with the structure placed on top. What was it's purpose?
To me it's a Crusher Anvil.
Please obserb the pounding marks starting from the top.
3 or 4 large at the top working down to many small ones at the bottom.
With a timber or log gantry erected on all 3 sides wider at the top narrowing towards the bottom of the anvil quarried material would have been delivered and crushed to fines by horizontal pole pounders supported by an extension of the gantry above .
The lower pounding poles may have been hand operated.
As the material had to be transported to a distant site firing the trenches was oviously not an option the calcined material would have set by absorbing atmospheric moisture before arrival.
The quarry is made up of SOFT sandstone so no great effort was required in the extraction process.
Before I proceed any further a few things should be drawn to your attention.
Petrie referred to most excavations as ROCK-CUT however I don't believe this was the case!
Take for example if you were required to excavate a 4 foot square 20 foot deep shaft into a sedimentary layered material, what would you do to stabilizes the walls so they wouldn't cave in?
To the AE's the answer would have been simple, excavate the first 5 to10 feet, build a fire in the excavation, calcine the walls and allow the atmospheric moisture or moisture already in the surrounding material to be absorbed back into the calcined walls, this would have stabilized the walls and given them an appearance that looked like natural ROCK.
Where Petrie compares good workmanship to rough workmanship in regards to certain surfaces I attribute this to the amount of ware that took place on them rather than the quality of the actual finishes.
Gypsum and Limestons Kilns;
http://www.ucl.ac.uk/~ucfbrxs/limes/Kilns.htm
http://www.limehousekilns.ca/history.htm
(Quote; "Lime is one of the oldest products known to man, and dates back to the stone age. Primitive kilns believed to have been used to produce lime during this era have been excavated and it is believed that lime is the first manufactured chemical to be used by man. In fact lime plaster in reasonably good condition has been found in the pyramids, some 4,500 years old.
Mixed with coal and burned at extremely high temperatures of up to 1,000 degrees centigrade the limestone or calcium carbonate yielded carbon dioxide and calcium oxide also known as quicklime. Although hard work, the method was easy: alternate layers of coal and limestone were tipped in the top of the kiln and the burnt remains removed through the small doors at the base.http://www.rothbury.com/village/around/tosson.htm ")
Not to Scale;
The Graphic above is a rough overlay of a Drawn Kiln with the "Trial" and some of the internal GP passages. ( NTS) (demonstration only.)
I will elaborate on the Internal Passages in the GP where I can produce evidence via pictures of ware marks to qualify my statement that the GP passages are nothing more than a ("Cement Factory production line") as we know it.
This is part of an article by Dr. Hawass, he later changed his opinion about the use of the passages:
(Quote;)"To the east of the Great Pyramid, Petrie found passages cut into the rock
floor that are very similar to the passages inside the Great Pyramid.
These he called "trial passages", thinking they were a trial run for
making the actual pyramid passage. The trial passages are just north of
the cause-way of Khufu beside the tomb of Hetepheres. They lie 87.50 m.
from the eastern base of Khufu's pyramid and 43.50 m. north of the
east-west axis.
The passages are oriented north to south, the rock was cut carefully and well squared, and some parts were encased with mortar.
The passages have a total length of 22 m. and a total vertical depth of
10 m. At the north end there is an opening in the bedrock when is cut
in steps. This becomes a sloping passage 1.05 m. wide and 1.20 m. high,
which continues at an angle of 26°3''. From the north entrance of this
passage, a second passage, of almost identical cross-sectional
dimensions, begins. This second passage ascends southward at
approximately the same angle as that by which the first passage
descends. At 5.8 m. from its beginning, this second passage reaches the
surface of the bedrock and widens into a
corridor which is open to the sky. A square shaft, about 0.72 m. m
width, was cut vertically from the surface of the bedrock
to the point where the two passages meet. About 6 m. west of the trial
passages and parallel to them is a long and narrow trench considered
the third trial passage. This runs parallel to the other passages, and
is almost exactly equal in width to the vertical shaft in the trial
passages. Its southern end is well-cut but its northern end was left
rough. It measures 0.15 m. deep at the north end and 0.43 m, deep at
the south end. This narrow trench is 0.71 m. wide and 7.35 m. long."
Lime Pit Kiln;
This trench was clearly used for calcining Gypsum and Limestone.
Yellow = Calcined crust formations.
Enclosed red area = Rock-like crust removed exposing weaker material behind.
The next photo shows the close proximity of the so called "Trial Passages" to the above Pit.
Maybe a connecting passage between the subterranean passage and the Pit Trench existed? This would have made recovery a lot easier also it would have been a good place for starting fuel to kick start the Pit fire. ( hypothectical only)
Here is a way of understanding the basic construction method of constructing this Obelisk.
Firstly examine the pictures below in fine "DETAIL"
More detailed pictures here;
http://www.waseda.jp/prj-egypt/sites/Aswan/AswanPh-E.html
Details to look for:
- Color of the surrounding rock, color of the Obelisk and color of the material between the surrounding rock and the Obelisk.
- Natural Strata cracks in the surrounding rocks
compared with the lack of them in the Obelisk.
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The pounding marks on the top of the Obelisk especially the edges and the sides of the tapered surfaces
- Also the lack of pounding grooves on top of the main body of the Obelisk.
- Notice the pounding grooves in relation to the bench on the lower right hand corner of the picture, they do not penetrate the ledge. Why? "TO HARD"
- The right hand side of the excavation has straight lines where as the left hand side shows strata cracks all over the place.
- The type of fault crack emanating from the wedge groove. This is not a Strata type crack, it has all the hallmarks of a man made substance.
Picture below;
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Note the pounding grooves only show on the lighter colored material.
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The strata, color and texture of the background material to the lighter material with the grooves.
In both circumstances the AEs formed a mould;
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Firstly by excavating a section of unstable rock via the strata cracks. The size of the the excavation would be approximately 2 feet wider than the object to be moulded allround.
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A floor is graded and finished to a flat surface in the excavation.
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A plug made up "brickettes" and laid with dry sand to form a shape, in this case an Obelisk.
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Stabilized sand is then added to the trench between the plug and the surrounding Granet to a level corresponding with the top of the Obelisk.
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PLAN or Overhead View;
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From there the plug is removed and the stabilized sand is dressed to the shape required while still moist but not hard.
All that is required now is to fill the mould with a run down of Granite "Chips" collected and screened from the quarry floor mixed with their Calcined product in the mould.
Rock Pounders can now be employed to pound out the "Stabilized Sand" not Granite to release the moulded form.
MAKE YOUR OWN MIND UP?
Clearly it can be seen the original soft creamy colored material is exposed under the Rock-like Crust.
This crust has been calcined and set off by moisture, so why call it natural ROCK?
Well to me it's; "Keep the MYSTERY alive and Milk The Cash-Cow for as long as you can."
FINDING THE GEOMETRY.
A short explanation as to how I found the new Geometry for the GP.
The graphic #1 contains 120 divisions, #2 was my interpretation, #3 was just an idear, #4 by extending the arc of the head and cape then rotating the red area in the direction of the arrow to link up with the arc the red and white lines will line up with the yellow lines. The purple triangle was superimposed by myself.
#5 My interpretation, #6 scaled dimensions added.
The CAD image below sets the ball rolling. Buy adding half the hypotenuse to the height plus the base we get 38. If we add half the extended hypotenuse; 4 to ( 20 + 16 + 12 ) = 52.
Total up all the #s = 56; Angle at top = 36.869 degrees.
The diameter of the circle is 36.
By dividing the circle with 120 divisors and numbering them 1 to 120 anticlockwise I noticed the extended hypotenuse intersected with the circumferenc at a point or space between 36 and 37. By enlarging the space between the #s 36 and 37 with my scanner I found that it intersected at scaled out position of 52 is to 60 whitch equates to; ( 52/60 ) = 0.8666+.
By
adding the # 36 to .866 = 36.866+ It should become ovious why I took
particular interest in such a configuration. = (36.86 is the angle at
the top of the triangle)
At this point I had to know where 36.75 fitted into the picture as 36.75 x 3.1428571 = 115.5 or 36.75 x 3.143 = 115.50525 also add (36+75) = 111
Unusal Triangle;
(A) 16.294/2 = 147
(B) Place a zero behind the 12 = 120 add to 804 = 924
(C) place a zero behind the 20 = 200 add to 724 = 924
924/4 = 231. ( 231/.525) = 440
147/.525 = 280
440/280 = 1.5714285714285714285714285714286
1.5714285714285714285714285714286 x 2 = 3.1428571+
Below is a CAD graphic as an exersise divide each of the numbers below by 11
Listed your answers?
Now in the same order divide the numbers fron "behind" by 11
Example; (264/11) = 24; (264/11b/w) = 24
264/2 b-wards = 231
396/3 b-wards = 231
Add all the #s 264+396+660+528 = 1848 /(3.1428571) = 588 /(2) = 294 /(2) = 147
Add 660 + 528 = 1188
Sup. Hypotenuse. 186.06
Enhanced image above indicates;
(1) 8.9 Yellow Twists at Eye Junction.
(2) Full Eyeball flattened, (indented). = 90.
(3) Eye Whites ether side of eyeball;
= 1 + 1/2 (1.5)
Storyline. Full eye appears to be squashed "indented".
Left h/s corner eye socket indicates twist "combine".
(Combining of the two half sides at the indent point.)
Full Eye and Eye Whites to be used calculating Eye Values.
Lower Section Values
Lower Eye Socket. = 180.
Tail V = 11.
Leg V = 13.
Calculation (180/11/13) = 1.258.
Upper Half Values.
Eye Cavity V = 135 (Eye = 90 "Eye whites" = 1&1/2 (90*1&1/2) = 135)
Left Hand Side Twists at Junction;
= 8.9 (last on left smaller than rest).
Eyelashes = 4.
Calculation. (135 + 8.9 + 4) = 147.9.
Length of Sup. Hypotenuse;
= (1.258 * 147.9) = 186.06
It is now possible to calculate the length of the Sup. Base on the South side.
Calculation. (186.06 * 186.06) - (146.784 * 146.784) = 13072.78.
(13072.78 Square Rooted) = 114.34.
146.784m is obtained by subtracting half rise from S/E. corner to the S/W. corner.
Cal. 147 - (432mm /2) = 146.784m.
http://eohpyratech.conforums.com/index.cgi
EOH CIRCUMFERENCE IMAGE DECODED
ANCIENT CONSTRUCTION METHODS "NEW"
THE ROYAL CUBIT ROD ( HOME )
1 on the Royal Cubit Rod Homepage.
Height Decoding;
The Eye holds the secret as to the outcome of the mathematics.
The vertical lines in the Leg and above the Tail indicate that this image relates to the height of the GP.Height of GP = 147
The Lower Eye Socket in this style (Leg) = 180
Lower Half Values
Lower Eye Socket = 144 (180 *.8) re. (.2 of eyeball concealed behind lower socket).
Tail V = 11.4 (4 verticals above curl of tail indicate + (.4).
Leg V = 13.3 (3 verticals in leg indicate + (.3).
Calculation for Lower Section;
(144/11.4) = 12.63 / (13.3) = .949
Top Half Values.
Eyeball V = 90 (top of eye fully exposed below Upper Eye Socket).
Eye Whites V = 135 (1.5*90). (1 and 1/2 pieces over white eyeball areas).
Number of verticals between Upper Eye Socket & Eyebrow = 14.9.
Eye Brow = 5
Total value for Upper Eye Section = (135 + 14.9 + 5) = 154.9
Height Calculation. (.949 * 154.9) = 147
Please
note, the Height of 147m. only relates to the Basic Design Height of
the GP above the level of the top of the Socket Block at the South East
corner.
Special Note; 360 square rooted =18.974 Divided by 20 = .949
EOH CIRCUMFERENCE IMAGE DECODED
EOH SUP. HYPOTENUSE IMAGE DECODED
ANCIENT CONSTRUCTION METHODS "NEW"
Circumference = 924;
Please examine the images below closely!
Note;
(1) Detail in the Leg.
(2) Curls in the tail.
What do they suggest?
(1) Indicates; Corners.
(2) Indicates; Circumference!
The above image is original.
ENHANSED VERSION BELOW;
Circumference.
The Lower Eye Socket Value for this style of image = 180
Lower Eye Section
Lower Eye Socket = 180.
Tail V = 5.5 (2 extra curls = 11/2)
Leg V = 4.25 (8.5 divisions on each side of dividing line (8.5/2)
Calculation lower half;
(180 / 5.5 / 4.25) = 7.7
Top Eye Section…. (Option (1)
Eye Cavity V = 2/3 (Eyeball showing 2/3).
Upper Eye Socket V = 180 (one split in two (2*90) = 180.
Calculation V = (180*2/3) = 120.
Top Eye Section…. Option (2)
Eye Whites V = 1&1/3 (by seize)
Eye Cavity V = 80 (Eyeball showing (2/3 of 90) =60. (60*1&1/3)= 80.
Eye Lash V = 40 (divisions, hard to count).
Calculation. (80+40) = 120.
Circumference of Original BASIC Design;
(7.7*120) = 924
The Picture tells the story.
Notice the way the divisions are positioned on the "leg".
This resembles the corners of the GP.
Every image has its own little message, whether it belongs to the artist or by the design.
http://eohpyratech.conforums.com/index.cgi
EOH SUP. HYPOTENUSE IMAGE DECODED
ANCIENT CONSTRUCTION METHODS "NEW"
Half Base length for the SE corner.
Lower Eye Values.
Tail; V = 11.1
Leg; V = 23.3 (Pad Spur = 10) + (Leg = 13) + (Nodes .3)
Lower Eye Socket; V = 520
Eye covered by LES. V = .2
Lower Section calculation;
(520 * .8) / (11.1) = 37.47/ (23.3) = 1.6
Lower Section V = 1.6
Upper Eye Values.
Eyeball V = 45 (.5 showing).
Eye Whites" V = 1&1/3(showing).
Stones above Eye Socket" V = 7.2 (7 large + one small; .2)
Eyebrow V = 5.
Total top eye values = (45*1.333) = 59.99 + 7.2+5 = 72.19
Calculation... (1.6 * 72.19) = 115.5 Half Base.
115.5m Being the original Basic Start Length from the South East corner in the Design Theory for the Great Pyramid.
EOH CIRCUMFERENCE IMAGE DECODED
EOH SUP. HYPOTENUSE IMAGE DECODED
ANCIENT CONSTRUCTION METHODS "NEW"
2. Air Shafts
3. King's Chamber
4. Ante-chamber
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